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Dat Do edited beginproblem_a_You_a.tex
about 10 years ago
Commit id: 15f7bd9e5e08725fff55ecf855ccd39b2e85b7bc
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(b) Since we are still receiving one extra coupon for each consecutive day, $\sum\limits_{i=1}^n i$ can still represent the number of coupons received. However, the value of the coupons is: $1 + 2 + 4 + \ldots+ (n-1) + 2(n-1)$ which can be represented as $\sum\limits_{i=1}^n 2^{n-i}$.
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We must multiply the quantity and the value together during each sum to get the total value resulting in: $W(n) = \sum\limits_{i=1}^n i*2^{n-i}$
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(c) For $n = 1$ through $n = 6$,
\begin{itemize}
\item $W(1) = 1$