Benedict Irwin edited section_Fermat_Like_Problem_Observing__.tex  over 8 years ago

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which represents the equivalence (as $x\to\infty$) \begin{equation}  \frac{a^0+b^0}{x}-\frac{a^1+b^1}{x^3}+\frac{a^2+b^2}{x^5}-\cdots = \frac{c^0}{x}-\frac{c^1}{x^3}+\frac{c^2}{x^5}-\cdots  \end{equation}  The basic comparison is then \begin{equation}  (n=0)\;\;\;\lim_{x\to\infty} 2=1\;\;\;(\mathrm{no solution})  \end{equation}