Benedict Irwin edited section_Further_Finite_Sequences_begin__.tex  about 8 years ago

Commit id: 6e35a79adcbe88a3eb7fb3e8f1e52528fd8dd8d9

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we see the Delannoy numbers above have fractional coefficients of the form \begin{equation}  C=1\\  s^{(1)}_n = \frac{2^n+1}{2^{n-1}+1}\;\; n>1 \\ \frac{2^n+1}{(1-\delta_{n,1})(2^{n-1}+1)+\delta_{n,1}}\\  s^{(2)}_n = \frac{2^n+2}{2^{n}+1}  \end{equation}