Benedict Irwin edited section_Fermat_Like_Problem_Observing__.tex  over 8 years ago

Commit id: 001176807e39cb2134d30c4b0c2fa093c2435852

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for this we only have solutions $b=-a,c=0$ and $b=a,c=2a$. We perform the next step and solve  \begin{equation}  \lim_{x\to\infty} \lim_{x\to\infty}\left[  \frac{2x^3}{  x+\frac{\frac{a+b}{2}}{  x+\frac{\frac{(a-b)^2}{a+b}}{  x+\frac{\frac{2ab}{a+b}}{  x}}}} -2x^2 + a + b -\frac{x^3}{x+\frac{c}{x}} +x^2 -c =0 \right]=0  \end{equation}  This has solutions \begin{equation}  b=-a,\;c=0\\  \end{equation}