Benedict Irwin edited section_Infinite_Series_and_Non__.tex  over 8 years ago

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x=\log_{[\zeta(1)]}(a)\\  \log_{[\zeta(1)]}(\zeta(2))=2\\  \log_{[\zeta(1)]}(\zeta(3))=3\\  \end{equation}  Then we see that (at least for the basic support) \begin{equation}  \log_{[\zeta(1)]}(\zeta(s))=s  \mathrm{inv}[\zeta(s)]=\log_{[\zeta(1)]}(s)  \end{equation}