Benedict Irwin edited untitled.tex  over 8 years ago

Commit id: 75b7752052843a103d2374cea90fd9cb0a8eff50

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\end{equation}  this gives \begin{equation}  \alpha \log \ln  13 + \beta = 2\\ \alpha \log \ln  35 + \beta = 3 3\\  \alpha = \frac{1}{\ln \frac{35}{13}}=1.00969...\\  \beta = 2-\frac{\ln 13}{\ln \frac{35}{13}}=-0.58981...  \end{equation}