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Benedict Irwin edited section_Sum_of_Three_Cubes__.tex
over 8 years ago
Commit id: 08f7261ab3a809f86dd3d69f969e931664ec6fa7
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We find that \begin{equation}
\lim_{x\to\infty}\frac{\log_{[2,3,4](x)}}{\log_{[3,4,5]}(x)}=\frac{1}{2}\frac{\ln(5)}{\ln(2)} \lim_{x\to\infty}\frac{\log_{[2,3,4]}(x)}{\log_{[3,4,5]}(x)}=\frac{1}{2}\frac{\ln(5)}{\ln(2)}
\end{equation}
