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Benedict Irwin edited untitled.tex
over 8 years ago
Commit id: d019c35c40c638dfc19204ea6f01b4ae0c26acef
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index c9ba12a..b786719 100644
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for any value of $n$! That is the entropy of each state is the same, independant of the level of excitation.
When adjusting for waves of any amplitude $\alpha$ we get \begin{equation}
\int_0^\pi \alpha^2sin^2(nx)\mathrm{ln} \alpha^2sin^2(nx) \; dx
=\frac{\pi\alpha^2}{2}(1-\mathrm{ln}(4\alpha^2)) =\frac{-\pi\alpha^2}{2}(1-\mathrm{ln}(\frac{4}{\alpha^2}))
\end{equation}