Benedict Irwin edited General Solution.tex  over 9 years ago

Commit id: 95512dc2e085246b9eb239b8d38c11636060fd18

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\frac{d^2\psi(x)}{dx^2}=\bigg( G + G^2 - \frac{kGV'}{\alpha-V} + \\  \frac{k\alpha V'' + kVV'' -\alpha V'G + VV'G -V'V'}{(\alpha -V)^2} + \\  \frac{\alpha k V'V' - VkV'V'}{(\alpha - V)^3} \bigg) \psi(x)  \end{equation}