Benedict Irwin edited General Solution.tex  over 9 years ago

Commit id: 948c6ff1999787c9a8091f9c83e69b69d15e31a8

deletions | additions      

       

\end{equation}  and then \begin{equation}  \frac{d^2\psi(x)}{dx^2}=\bigg( G + G^2 - \frac{kGV'}{\alpha-V} + \\  \frac{k\alpha V'' + kVV'' -\alpha V'G + VV'G -V'V'}{(\alpha -V)^2} + \\  \frac{\alpha k V'V' - VkV'V'}{(\alpha - V)^3}  \end{equation}