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Benedict Irwin edited General Solution.tex
over 9 years ago
Commit id: 335b896cb7c9c1c0053da31bc78b7352bc9c8820
deletions | additions
diff --git a/General Solution.tex b/General Solution.tex
index 14c6252..a843090 100644
--- a/General Solution.tex
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In this circumstance we have \begin{equation}
\frac{d\psi(x)}{dx}=G(x)\psi(x)-\frac{kV'(x)\psi(x)}{\alpha-V(x)} \frac{d\psi(x)}{dx}=-V(x)G(x)\psi(x)-\frac{kV'(x)\psi(x)}{\alpha-V(x)}
\end{equation}
"RECHECK WORKING FROM THIS POINT MAY HAVE MISSED A FACTOR OF V(x)"
and then \begin{equation}
\frac{d^2\psi(x)}{dx^2}=\bigg( G' + G^2 - \frac{kGV'}{\alpha-V} +