Benedict Irwin edited section_Some_2D_Vector_Results__.tex  almost 9 years ago

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\end{equation}  This means, any original matrix without any anti-diagonal elements ($c=e=g=0$), preserves a one to one mapping.  Or any matrix without half of the skew elements ($b=d=i=0$), also preserves a one to one mapping. If we add $3$ as well, to complete the set of two digit binary numbers \begin{equation}  \begin{bmatrix}0\\3\end{bmatrix}\to  \begin{bmatrix}0&0\\1&1\end{bmatrix}\to  \begin{bmatrix}0&1\\0&1\end{bmatrix}\to  \begin{bmatrix}1\\1\end{bmatrix}\\  \begin{bmatrix}1\\3\end{bmatrix}\to  \begin{bmatrix}0&1\\1&1\end{bmatrix}\to  \begin{bmatrix}0&1\\1&1\end{bmatrix}\to  \begin{bmatrix}1\\3\end{bmatrix}\\  \begin{bmatrix}2\\3\end{bmatrix}\to  \begin{bmatrix}1&0\\1&1\end{bmatrix}\to  \begin{bmatrix}1&1\\0&1\end{bmatrix}\to  \begin{bmatrix}3\\1\end{bmatrix}\\  \begin{bmatrix}3\\3\end{bmatrix}\to  \begin{bmatrix}1&1\\1&1\end{bmatrix}\to  \begin{bmatrix}1&1\\1&1\end{bmatrix}\to  \begin{bmatrix}3\\3\end{bmatrix}\\  \begin{bmatrix}3\\2\end{bmatrix}\to  \begin{bmatrix}1&1\\1&0\end{bmatrix}\to  \begin{bmatrix}1&1\\1&0\end{bmatrix}\to  \begin{bmatrix}3\\2\end{bmatrix}\\  \begin{bmatrix}3\\1\end{bmatrix}\to  \begin{bmatrix}1&1\\0&1\end{bmatrix}\to  \begin{bmatrix}1&0\\1&1\end{bmatrix}\to  \begin{bmatrix}2\\3\end{bmatrix}\\  \begin{bmatrix}3\\0\end{bmatrix}\to  \begin{bmatrix}1&1\\0&0\end{bmatrix}\to  \begin{bmatrix}1&0\\1&0\end{bmatrix}\to  \begin{bmatrix}2\\2\end{bmatrix}\\  \end{equation}