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Benedict Irwin edited Introduction.tex
almost 10 years ago
Commit id: 4b39a1922d2d805d60aba52fc9025d24b06e24d9
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...
s^+s|n>=\sqrt{n+\frac{1}{2}}|n> \\
r^+r|n>=\sqrt{n}|n> \\
ss^+|n>=\sqrt{n+1}|n> \\
rr^+|n>=\sqrt{n+\frac{1}{2}}|n> rr^+|n>=\sqrt{n+\frac{1}{2}}|n>\\
\\
sr^+=\sqrt[4]{n+\frac{1}{2}}\sqrt[4]{n+1} \\
rs^+=sr^+, Herm.. \\
r^+s=\sqrt[4]{n}\sqrt[4]{n+\frac{1}{2}} \\
s^+r=r^+s, Herm...
\end{equation}
So we have mixed hermitian eigenoperators of state |n>.
Which means a double application of r^+r is equal to the number operator N=a^+a, a double application of ss^+ is equivalent to the operator $aa^+$ and it implies that $s^+s \equiv rr^+$. This is interesting, we can measure the number of particles in an oscillator by only taking half of one out and putting it back (r then r^+ is the operation r^+r), but there are two ways to take the particle out and two ways to put it back and each appear as different actions with different 'compensations'.
These sub-operations work in line with the conjugate operation. if we introduce a basic ladder opperator with no coefficients \begin{equation}