Benedict Irwin edited Stable Number Operator.tex  almost 10 years ago

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An eigenstate for a ternay triplet was found. Define:  \begin{equation}  a^r_+|\alpha>=\sqrt[3]{\alpha}|\alpha+\frac{2}{3}> r^+|\alpha>=\sqrt[3]{\alpha}|\alpha+\frac{2}{3}>  \\ a^r_-|\alpha>=\sqrt[3]{\alpha}|\alpha-\frac{1}{3}> r|\alpha>=\sqrt[3]{\alpha}|\alpha-\frac{1}{3}>  \\ a^g_+ g^+  \\ a^g_-|\alpha>=\sqrt[3]{\alpha-\frac{2}{3}}|\alpha-\frac{1}{3}>\\  a^b_+ g|\alpha>=\sqrt[3]{\alpha-\frac{2}{3}}|\alpha-\frac{1}{3}>\\  b^+  \\ a^b_-|\alpha>=\sqrt[3]{\alpha-\frac{1}{3}}|\alpha-\frac{1}{3}> b|\alpha>=\sqrt[3]{\alpha-\frac{1}{3}}|\alpha-\frac{1}{3}>  \end{equation}  Then the operation \begin{equation} 

a^b_-a^g_-a^r_+|\alpha>=\alpha|\alpha>  \end{equation}  and then acts like a number operator Then there are operations:  \begin{equation}  a^ra^ba^g|\alpha>=(\alpha-\frac{2}{3})|\alpha-1> \\  ... \\  bgr|\alpha>=  \end{equation}  Hamiltonian basic version:  \begin{equation}  H=Wbgr^+\\  \end{equation}  TERNARY COMMUTATOR?  [a,b,c]=abc-acb-bac+bca+cab-cba