Benedict Irwin edited Ternary Ladders.tex  almost 10 years ago

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\section{Ternary Ladders}  Based on quarks Define: \begin{equation}  a|\alpha>=\beta^{\alpha}_a|\alpha-\frac{1}{3}> \\  a^+|\alpha>=\beta^{\alpha}_{a^+}|\alpha+\frac{2}{3}> \\  \\  and\\  \\  \hat{a}|\alpha>=\beta^{\alpha}_{\hat{a}}|\alpha+\frac{1}{3}>\\  \hat{a}^+|\alpha>=\beta^{\alpha}_{\hat{a}^+}|\alpha-\frac{2}{3}>  \end{equation}