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Benedict Irwin edited Ternary Ladders.tex
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\section{Ternary Ladders}
Based on quarks
Define: \begin{equation}
a|\alpha>=\beta^{\alpha}_a|\alpha-\frac{1}{3}> \\
a^+|\alpha>=\beta^{\alpha}_{a^+}|\alpha+\frac{2}{3}> \\
\\
and\\
\\
\hat{a}|\alpha>=\beta^{\alpha}_{\hat{a}}|\alpha+\frac{1}{3}>\\
\hat{a}^+|\alpha>=\beta^{\alpha}_{\hat{a}^+}|\alpha-\frac{2}{3}>
\end{equation}