Benedict Irwin edited Stable Number Operator.tex  almost 10 years ago

Commit id: 59e575acea080b3ce36d2d3f5c9ab9b51b4bb577

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\hline  bgr^+ & \alpha \\  br^+g & \sqrt[3]{\alpha}\sqrt[3]{\alpha-\frac{1}{3}}\sqrt[3]{\alpha-\frac{2}{3}} \\  gbr^+ & \sqrt[3]{\alpha}\sqrt[3]{\alpha+frac{1}{3}}\sqrt[3]{\alpha-\frac{1}{3}} \sqrt[3]{\alpha}\sqrt[3]{\alpha+\frac{1}{3}}\sqrt[3]{\alpha-\frac{1}{3}}  \\ gr^+b & \alpha -\frac{1}{3} \\  r^+bg & \alpha -\frac{2}{3} \\  r^+gb & \sqrt[3]{\alpha-1}\sqrt[3]{\alpha-\frac{1}{3}}\sqrt[3]{\alpha-\frac{2}{3}} \\  \hline  \end{array}  \end{equation}  Thus \begin{equation}  [b,g,r^+]=\alpha - \sqrt[3]{\alpha}\sqrt[3]{\alpha-\frac{1}{3}}\sqrt[3]{\alpha-\frac{2}{3}} - \sqrt[3]{\alpha}\sqrt[3]{\alpha+\frac{1}{3}}\sqrt[3]{\alpha-\frac{1}{3}} + (\alpha -\frac{1}{3}) + (\alpha -\frac{2}{3}) - \sqrt[3]{\alpha-1}\sqrt[3]{\alpha-\frac{1}{3}}\sqrt[3]{\alpha-\frac{2}{3}}  \end{equation}