deletions | additions       diff --git a/Ternary Ladders.tex b/Ternary Ladders.tex  index b0483fc..00eed11 100644  --- a/Ternary Ladders.tex  +++ b/Ternary Ladders.tex 
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\end{equation}  So considering the $\beta$ terms. The only time $\beta^{\alpha-\frac{2}{3}}_a$ might arise is if an a has operated on a state that is already filled by $\alpha-\frac{2}{3}$. So, it should seem appropriate that if $\alpha=0$ this coeficcient drops to zero to prevent negative integer fillings.  One could forsee that if the is a base number operator $N=aaa^+$ then combinations of these transitions could be such that \begin{equation}  (aaa)(a^+a^+a)|\alpha> = a(aaa^+)a^+a|\alpha>