Benedict Irwin edited Splitting the Num.tex  almost 10 years ago

Commit id: bd3407f527cca28f9a4150b4b63fc5fddc612706

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There exist non symmetric (Irwin-Worthy, lololol) solutions to the equation \begin{equation}  4cos^2(\theta)cos^2(\varphi) = cos^2(\theta)+2cos(\theta)cos(\varphi)+cos^2(\varphi) cos^2(\theta)+2cos(\theta)cos(\varphi)+cos^2(\varphi)\\  4(cos(\theta)cos(\varphi))^2=(cos(\theta)+cos(\varphi))^2  \end{equation}