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Benedict Irwin edited Prime Factors.tex
almost 10 years ago
Commit id: 39ce4bbcccf422da3b9837a55915a8faab122a76
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index f996e14..386eaee 100644
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But then there are states such as \begin{equation}
|1,1,0> \cdot |1,1,1> = 2
\end{equation}
which are 'doubly' non-orthogonal. They share two prime
divisors. divisors.\
We can try to imagine a small number space. There is a vertical axis $1$ which is orthogonal to a multi dimensional "plane" or volume below. In this multidimensional volume we could imagine a $2$ axis and as $3$ axis both orthogonal to each other and $1$ so forming a right handed set. Then we accept a dimensional folding such that the $0$ axis is also aligned with both $2$ and $3$. However, an axis for $6$ would also be aligned with both $2$ and $3$. If we included no other numbers here, so a numeral system where only the values $0,1,2,3$ and $6$ exist, then $6$ lies in the same orientation as $0$!! (Unless $0$ is not orthogonal to $1$). If we repeat this exercise, by making the largest number which is the product of all defined axes, then it will be aligned with all of the numbers, except $1$. Zero would also be aligned with all of the numbers, meaning the highest number created by the multiplication of all axis defined numbers is in the same orientation as the zero axis! Extrapolating this, infinity would be in the same orientation as zero.