deletions | additions       diff --git a/Higher Compounds.tex b/Higher Compounds.tex  index 10d1f2d..d739d08 100644  --- a/Higher Compounds.tex  +++ b/Higher Compounds.tex 
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\end{equation}  As a test, there can be $2p\otimes 3p\otimes 5p$, and the matrix $2p \otimes 3p$,  Then by summing over two indicies, there will be left the vector representing $5p$. The only element that is one in the cube will be element $N_{123}$. The only element that is one in the matrix will be $M_{12}$. Thus we must have the product in the form \begin{equation}  \odot^1 := \sum_{i}\sum_{j} M_{ij}N_{ijk}=v_{k}  \end{equation}  and as a result, $v=[0,0,1].