Benedict Irwin edited Predictions.tex  over 9 years ago

Commit id: 6b7a1966cadca5c9439d8afbb43f5595a79b1df4

deletions | additions      

       

In general, for any digit of $2^n$, which is $p$ places away from the least significant, if \begin{equation}  (n-p) \; mod \; 4\cdot5^p = k ,\;\; p\in[0,\infty],  \end{equation}  the $p^{th}$ least significant digit is $D_p(k)$, that is the $k^{th}$ term in the series $D_p$. Thus by knowing that $D_0(1)=2$,$D_1(12)=9$,$D_2(11)=1$,$D_3(10)=8$. We can tell that the number $2^{50000013}$, must end in the digits $8192$.