Benedict Irwin edited Investigation.tex  over 9 years ago

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\lim_{n\to\infty} \frac{1|3;n}{d|8;n}=\frac{12}{(d|8) - d}  \end{equation}  Then we have  \begin{equation}  \lim_{n\to\infty} \frac{1|2;n}{0|8;n} = 1.375\overline{0} =\frac{11}{8} \\  \lim_{n\to\infty} \frac{1|2;n}{1|8;n} =0.\overline{6470588235294117} = \frac{11}{17} \\  \end{equation}