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Benedict Irwin edited 9090+3.tex
over 9 years ago
Commit id: e950efb636fbc745686cc1294ab99a16cef1c42e
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We see that if $n+1=9m\in\mathbb{Z^0}$, then $(90;;n)-1$ is div by $19$. [8th prime] \\
We see that if $n+2=11m\in\mathbb{Z^0}$, then $(90;;n)-1$ is div by $23$. [9th prime] \\
We see that if $n+5=14m\in\mathbb{Z^0}$, then $(90;;n)-1$ is div by $29$. [10th prime] \\
We see that if $n+14=30m\in\mathbb{Z^0}$, then $(90;;n)-1$ is div by $43$. [14th prime]
\\ [DUBIOUS! CHECK THIS ONE]\\
We see that if $n+28=30m\in\mathbb{Z^0}$, then $(90;;n)-1$ is div by $61$. [18th prime] \\
We see that if $n+13=33m\in\mathbb{Z^0}$, then $(90;;n)-1$ is div by $67$. [19th prime] \\
We see that if $n+6=13m\in\mathbb{Z^0}$, then $(90;;n)-1$ is div by $79$. [22nd prime] \\