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Benedict Irwin edited Primality.tex
over 9 years ago
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We note that $n\in\mathbb{P}$ that are not $2$ appear to have two, larger primes introduced as divisible factors. (sometimes more? $13$. [semiprime?].
\section{Theorem 1} \begin{theorem}[Theorem 1]
$\forall \; p\in\mathbb{P}, n\in\mathbb{Z}\;:\;1;pn$ is divisible by $1;p$.
\end{theorem}
\begin{proof}[Proof]
Automatically true for $n=1$. \\
\end{proof}
$10$,$12$,$14$, may or may not have some curious relationship as thier numbers are $9091,9901,909091$...$99990001$, Think [False concatenation of $90$ -> $(90;;3)+1$], [think added permutations], does this apply to $333667$ as $(3;3|6;3)+1$. This sounds ridiculous which is why it's exciting.