deletions | additions       diff --git a/The 90 Thing.tex b/The 90 Thing.tex  index 332945b..6b60132 100644  --- a/The 90 Thing.tex  +++ b/The 90 Thing.tex 
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we can see that if $n-3 = 7m\in\mathbb{Z^0}$, the number is divisible by $(90;3)+1$\\  we can see that if $n-4 = 9m\in\mathbb{Z^0}$, the number is divisible by $(90;4)+1$\\  If we extrapolate this relationship, we have if $n-q = (1+2q)(m\in\mathbb{Z^0})$, then $(90;n)+1/((90;q)+1) \in \mathbb{Z}$. Rephrasing this \begin{equation}  \frac{(90;n)+1}{(90;q)+1} \in \mathbb{Z}, \; \forall n,q : n-q \; \mathrm{mod} \; (1+2q) = 0  \end{equation}