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Benedict Irwin edited 9090+3.tex
over 9 years ago
Commit id: 8788c9235348f31669686850ab72d150789ad68b
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We can now see $13$ vertical period $2$ substrings. \\
10...,12...,54...,01...,76...,77...,90...,87...,67...,11...,90...,10...
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Let $q_H=1150747986191$, $p_H=q_H|0241657077100$, with $|$ a join.
\begin{equation}
\begin{array}
\hline
N & p? & fac & dig & square?\\
\hline
(p_H;;0)|q_H & 0 & 203279×5660929 & 13 & 0\\
(p_H;;1)|q_H & 0 & 23^2×67×77862675719×41698499254488057125923 & 39 & 0\\
(p_H;;2)|q_H & 0 & & 65 & 0\\
(p_H;;3)|q_H & 1 & (p_H;;3)|q_H & 91 & 0\\
(p_H;;4)|q_H & 0 & & 117 & 0 \\
(p_H;;5)|q_H & 0 & & 143 & 0 \\
(p_H;;6)|q_H & 1 & & 169 & 1 \\
(p_H;;7)|q_H & ... & & 195 & 0 \\
\hline
\end{array}
\end{equation}
The origin of such repeating sequences is clear, Due to the periodic occurences of prime factors, at every occurence we will have a periodic sequence, divided by some prime. Which then goes on to generate another pseudo periodic sequence.