Benedict Irwin edited 9090+3.tex  over 9 years ago

Commit id: 8788c9235348f31669686850ab72d150789ad68b

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\\  We can now see $13$ vertical period $2$ substrings. \\  10...,12...,54...,01...,76...,77...,90...,87...,67...,11...,90...,10...  \\  Let $q_H=1150747986191$, $p_H=q_H|0241657077100$, with $|$ a join.  \begin{equation}  \begin{array}  \hline  N & p? & fac & dig & square?\\  \hline  (p_H;;0)|q_H & 0 & 203279×5660929 & 13 & 0\\  (p_H;;1)|q_H & 0 & 23^2×67×77862675719×41698499254488057125923 & 39 & 0\\  (p_H;;2)|q_H & 0 & & 65 & 0\\  (p_H;;3)|q_H & 1 & (p_H;;3)|q_H & 91 & 0\\  (p_H;;4)|q_H & 0 & & 117 & 0 \\  (p_H;;5)|q_H & 0 & & 143 & 0 \\  (p_H;;6)|q_H & 1 & & 169 & 1 \\  (p_H;;7)|q_H & ... & & 195 & 0 \\  \hline  \end{array}  \end{equation}  The origin of such repeating sequences is clear, Due to the periodic occurences of prime factors, at every occurence we will have a periodic sequence, divided by some prime. Which then goes on to generate another pseudo periodic sequence.