Benedict Irwin edited The 21 thing.tex  over 9 years ago

Commit id: 40f1c769761940aa4a0248ead42291c40de3d5ef

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\end{equation}  showing the constant $k^n_N$ has $n \times N$ digits.  So we can obviously cross the constants with wrong length sequences, \begin{equation}  1k^4_1 = 1111 \\  2k^4_1 = 2222 \\  3k^4_1 = 3333 \\  4k^4_1 = 4444 \\  11k^4_1 = 12221 = 11111 + (1;3)|0 \\  22k^4_1 = 24442 = 22222 + (2;3)|0 \\  66k^4_1 = 73326 = 66666 + (6;3)|0 \\  21k^4_1 = 23331 = (2;4)|0 + 0|(1;4) \\  \\  d_1d_2k^n_1 = (d_1;n)|0 + 0|(d_2;n) \\    \end{equation}