deletions | additions       diff --git a/The 90 Thing.tex b/The 90 Thing.tex  index 6b60132..15d2b89 100644  --- a/The 90 Thing.tex  +++ b/The 90 Thing.tex 
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Rephrasing this \begin{equation}  \frac{(90;n)+1}{(90;q)+1} \in \mathbb{Z}, \; \forall n,q : n-q \; \mathrm{mod} \; (1+2q) = 0  \end{equation}  Moreover [check this next bit]  If there exists no $q$ in the range [...,...] that $n-q \; \mathrm{mod} \; (1+2q) = 0$, then $(90;;n)+1$ is prime ????