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Benedict Irwin edited Pascals.tex
over 9 years ago
Commit id: 350011b3cb00c4dce8a063cc038d9d294d37f8c7
deletions | additions
diff --git a/Pascals.tex b/Pascals.tex
index 8d00de7..7382aae 100644
--- a/Pascals.tex
+++ b/Pascals.tex
...
The third line is $(010;2);2$.\\
The n^{th} line is $010;2_1;2_2;2_3...;2_{n-1}$ \\
We can attempt similar triangles with other starting strings.
1
1;3= 111
111;3=
111
111
111 = 12321
12321;3=
12321
12321
12321 = 1367631
1367631;3
1367631
1367631
1367631
151807041
\begin{equation}
1 \\ 111 \\ 12321 \\ 13677631 \\ 151807041
\end{equation}