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Benedict Irwin edited Primality.tex
over 9 years ago
Commit id: 2ba33e884d784cd75d5ea02dd9091dbe4840e83b
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1;28 & 0 & 11×29×101×239×281×4649×909091×121499449 \\
1;29 & 0 & 3191×16763×43037×62003×77843839397 \\
1;30 & 0 & 3×7×11×13×31×37×41×211×241×271×2161×9091×2906161 \\
1;31 & 0 & 2791×6943319×57336415063790604359 \\
1;32 & 0 & 11×17×73×101×137×353×449×641×1409×69857×5882353 \\
1;33 & 0 & 3×37×67×21649×513239×1344628210313298373 \\
1;34 & 0 & 11×103×4013×2071723×5363222357×21993833369 \\
1;35 & 0 & 41×71×239×271×4649×123551×102598800232111471 \\
\end{array}
\end{equation}
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1;17n\in\mathbb{Z} & 2071723×5363222357 \\
1;18n\in\mathbb{Z} & 52579?? \\
1;19n\in\mathbb{Z} & 1;19 \\
1;20n\in\mathbb{Z} & 27961 \\
1;21n\in\mathbb{Z} & 10838689 \\
1;22n\in\mathbb{Z} & 513239
1;23n\in\mathbb{Z} & 1;23
1;24n\in\mathbb{Z} & 99990001
1;25n\in\mathbb{Z} &
\hline
\end{array}
\end{equation}
...
We note that $n\in\mathbb{P}$ that are not $2$ appear to have two, larger primes introduced as divisible factors. (sometimes more? $13$. [semiprime?].
$10$,$12$,$14$, may or may not have some curious relationship as thier numbers are
$9091,9901,909091$... $9091,9901,909091$...$99990001$, Think [False concatenation of $90$ -> $(90;;3)+1$],
[think added permutations], does this apply to $333667$ as $(3;3|6;3)+1$. This sounds ridiculous which is why it's exciting.
Groups of equal numbers of $9,0$, with $1$ added, sorted into all permutations. [One is prime??]
To find more factors, one could use the previously found factors to quickly divide the number.
For example if we wanted to find the prime factors of $1;50$, [given the previously foudn information of up to $1;25$], we may look at the divisors of $50$, $1,2,5,10,25,50$, and identify that the prime factorisation of $1;50$ will be $11×41×271×9091×21401×25601×182521213001xF$, where $F$ are the associated divisors with $n=50$. We know $1;50$ is not prime, as $50$ is not prime.
Task: construct a sieve of Sieve of Eratosthenes style algorithm which uses this concept as a test for primality?
Information required: The appending patterns of the form $d_1d_2...d_N;n$. This is a big task.