Benedict Irwin edited section_Another_Form_begin_equation__.tex  almost 8 years ago

Commit id: 9f1c18203c9efdc7f1ce3a9c910d736082ac777a

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then \begin{equation}  \sum_{q=1}^\infty \frac{1}{q}\sum_{p|q} px^q(1-x^q) = \log\left(\prod_{k=1}^\infty 1+x^{p_k} \right)  \end{equation}  we also have \begin{equation}  \sum_{q=1}^\infty \frac{1}{q}\sum_{d|q} dx^q(1-x^q) = \log\left(\prod_{k=1}^\infty 1+x^{k} \right)  \end{equation}