Benedict Irwin edited section_Another_Form_begin_equation__.tex  almost 8 years ago

Commit id: 54711094d25dfdebe6ef9e3f2294ce3dd31ae9a6

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\log\left(\prod_{k=1}^\infty q+x^k\right) = \frac{(-1+2a)x^2}{2a^2} + \frac{(1+3a^2)x^3}{3a^3}+\frac{(-1-2a^2+4a^3)x^4}{4a^4}+\frac{(1+5a^4)x^5}{5a^5}+\frac{(-1+2a^3-3a^4+6a^5)x^6}{6a^6}+\cdots  \end{equation}  So we clearly have \begin{equation}  \log\left(\prod_{k=1}^\infty q+x^k\right) = \sum_{q=2}^\infty \frac{(-1)^?x^q\sum_{d|q}da^{q(1-1/d)}}{qa^q} \frac{x^q\sum_{d|q}(-1)^?da^{q(1-1/d)}}{qa^q}  \end{equation}