deletions | additions       diff --git a/untitled.tex b/untitled.tex  index 6d18863..2c4b861 100644  --- a/untitled.tex  +++ b/untitled.tex 
...
\frac{df(x)}{d\mathbb{I}}=\frac{f((1-\delta)x)-f(x)}{(1-\delta)-1}  \end{equation}  In this manner  \begin{equation}  \frac{de^x}{d\mathbb{I}}=\frac{e^xe^{-\delta x}-e^x}{(1-\delta)-1}=\frac{e^x(1-\delta z)-e^x}{(1-\delta)-1}  \end{equation}