Benedict Irwin edited untitled.tex  over 9 years ago

Commit id: c687c96f192506a17be6d0e838c67cb7e7fedeb0

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\int_0^\infty e^{-x} dx =1 & \int_0^\infty -xe^{-x} dx = -1 \\  \int_0^\infty x^{z-1}e^{-x} dx= \Gamma(z) & \int_0^\infty x^{z-1}e^{-x}(-x+z-1) dx= -\Gamma(z) \\  \int_0^\infty x^{z-1}e^{-x}(-x+z-1) dx= -\Gamma(z) & \int_0^\infty x^{z-1}e^{-x} (x+x^2+(-1+z)^2-2xz)dx=\Gamma(z) \\  \int_-\infty^\infty 1 dx = \infty & \int_-\infty^\infty -1 dx = -\infty \\  \hline   \end{array}  \end{equation}