Benedict Irwin edited untitled.tex  over 9 years ago

Commit id: c32bfd76c427424a0dc18ffe4a9e8a58639c0b77

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One can create a formal definition which yeilds such a result that \begin{equation}  \lim_{\delta \frac{df(x)}{d\mathbb{I}}=\lim_{\delta  \to 0}\frac{df(x)}{d\mathbb{I}}=\frac{f(x)-f((1-\delta)x)}{\delta} 0}\frac{f(x)-f((1-\delta)x)}{\delta}  \end{equation} 

\begin{equation}  \frac{de^x}{d\mathbb{I}}=\frac{e^x-e^xe^{-\delta \frac{de^x}{d\mathbb{I}}=\lim_{\delta \to 0}\frac{e^x-e^xe^{-\delta  x}}{\delta}=\frac{e^x-e^x(1-\delta x)}{\delta}=xe^x \end{equation}