Benedict Irwin edited Explaination.tex  over 9 years ago

Commit id: c1212f72ad91f64a7fda4a0b366d125fb03f8b53

deletions | additions      

       

This progression continiues and one can find that \begin{equation}  \int_a^b x^nf^{(n)} \;dx = \sum_{k=0}^n \frac{(-1)^k}{k!}(-1)^nn!B_n \frac{(-1)^nn!}{(-1)^kk!}B_n  \end{equation}