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Benedict Irwin edited Explaination.tex
over 9 years ago
Commit id: c1212f72ad91f64a7fda4a0b366d125fb03f8b53
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This progression continiues and one can find that \begin{equation}
\int_a^b x^nf^{(n)} \;dx = \sum_{k=0}^n
\frac{(-1)^k}{k!}(-1)^nn!B_n \frac{(-1)^nn!}{(-1)^kk!}B_n
\end{equation}