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\lim_{a\to1}\big(\frac{d}{da}e^{ax}=xe^{ax}\big) = \big( \frac{d}{d\mathbb{I}}e^{x}=xe^{x} \big)  \end{equation}  One can create a formal definition which yeilds such a result that \begin{equation}  \frac{df(x)}{d\mathhbb{I}}=\frac{f((1-\delta)x)-f(x)}{(1-\delta)-1}  \end{equation}