Benedict Irwin edited untitled.tex  over 9 years ago

Commit id: 7040ba99110e2724f250848498222406e4bfb89f

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One can create a formal definition which yeilds such a result that \begin{equation}  \frac{df(x)}{d\mathhbb{I}}=\frac{f((1-\delta)x)-f(x)}{(1-\delta)-1} \frac{df(x)}{d\mathbb{I}}=\frac{f((1-\delta)x)-f(x)}{(1-\delta)-1}  \end{equation}