Benedict Irwin edited Integration summation.tex  over 9 years ago

Commit id: 0a66346c63e0222698346e90595f463d0a1a1d1c

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Does there exist an integral that equals $\zeta(s)$...  \begin{equation}  \zeta(s)=\frac{1}{\Gamma(z)}\int_0^\infty \zeta(s)\Gamma(z)=\int_0^\infty  \frac{x^{s-1}}{e^x-1} \; dx \\ \frac{d}{dx}\frac{x^{s-1}}{e^x-1} = \frac{(e^x (s-x-1)-s+1) x^{s-2}}{(e^x-1)^2} \\  \end{equation}  Therefor by the theory \begin{equation}  -\zeta(s)\Gamma(z)=\int_0^\infty \frac{(e^x (s-x-1)-s+1) x^{s-1}}{(e^x-1)^2} \; dx \\  \end{equation}