Benedict Irwin edited Weird Ideas.tex  over 9 years ago

Commit id: 4fc9b9eda4e1c42f5d7a05ef1ca2eacd4d446226

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Such that $\nabla^{-1}\mathbf{B}=\nabla^{-1}(\nabla\phi)=\phi$...  \begin{equation}  \nabla\cdot\mathbf{E}=\partial_y^{-1}\partial_z^{-1}E_x+\partial_x^{-1}\partial_z^{-1}E_y+\partial_x^{-1}\partial_y^{-1}E_z=\frac{\rho}{\epsilon_0}  \end{equation}  Which must be equal to something like \begin{equation}  \frac{\int_S \mathbf{E}\cdot\mathbf{dA}}{V}  \end{equation}