Benedict Irwin edited untitled.tex  about 8 years ago

Commit id: 1031ef7181bd512526f8ba074152319e89d500b4

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\begin{equation}  I[G(x)]=\frac{1}{1-G(x)}-1  \end{equation}  Let $I^{(n)}[G(x)]$ denote a repeated application of the invert transform $n$ times. We then have \begin{equation}  I^{(0)}[P(x)]=2x+3x^2+5x^3+7x^4+11x^5+\cdots\\  I^{(1)}[P(x)]=2x+7x^2+25x^3+88x^4+311x^5+\cdots\\  I^{(2)}[P(x)]=2x+11x^2+61x^3+337x^4+1863x^5+\cdots\\  \end{equation}