Benedict Irwin edited Complex.tex  over 9 years ago

Commit id: 79426826e2e515638e5df86e9b93db4e4cfd8792

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\mat{a}{b}{c}{d}^{-1}=\frac{1}{ac+bd}\mat{c}{c}{b}{-b}  \end{equation}  Which is very curious as it only relies on all of the elements weakly in the form of a coefficient. Even more odd is the fact that for the idenity matrix, whose cross inverse is clearly the hash identity, using the above formula leads to a definition of  an undefined quantity, \begin{equation} \frac{1}{0}\mat{0}{0}{0}{0} = \mat{1}{0}{1}{0}