this is for holding javascript data
Benedict Irwin edited Complex.tex
over 9 years ago
Commit id: 1d12e7004664211c6f9dc3e9a19696180fd9e351
deletions | additions
diff --git a/Complex.tex b/Complex.tex
index 5527c88..caf935b 100644
--- a/Complex.tex
+++ b/Complex.tex
...
\begin{bmatrix} 1 & 0 \\ 1 & 0 \end{bmatrix}\#\begin{bmatrix}a&b\\c&d\end{bmatrix}=\begin{bmatrix}a&b\\c&d\end{bmatrix}
\end{equation}
However it is not possible to define a right identity! Using the same matrix above will keep the elements the same bu swap those in the right hand column. Most likely a strange artifact of the way we came to the transform.
We can define a left inverse, for some $A\#B=C$ such that $(A^{-1}\#A)\#B=A^{-1}\#C=B$. For such a system we solve for the $a,b,c,d$ such that \begin{equation}
\begin{bmatrix} e & 0 & 0 &-h \\ f & 0 & 0 & g \\ 0 & -f & g & 0 \\ 0 & e & h & 0 \end{bmatrix}\begin{bmatrix}a \\ b \\ c \\ d \end{bmatrix}=\begin{bmatrix} 1 \\ 0 \\ 1 \\ 0 \end{bmatrix}
\end{equation}
Which results in \begin{equation}
A^{-1}=\frac{1}{eg+fh}\begin{bmatrix}g&h&0&0\\0&0&-h&g\\0&0&e&f\\-f&e&0&0\end{bmatrix}
\end{equation}\begin{bmatrix}1 \\ 0 \\ 1 \\ 0 end{bmatrix}