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a_3(n) = 2n-1  \end{equation}  we can use the Mathematica expression \begin{equation}  \mathrm{Simplify[InverseZTransform[F[1/z],z,n],Element[n,Integers]&&n>0]} \mathrm{Simplify[InverseZTransform[F[1/z],z,n],Element[n,Integers]\&\&n>0]}  \end{equation}  to extract the sequence function $a_3(n)$.