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Daniel D'Orazio edited untitled.tex
over 9 years ago
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...
\end{align}
Then
\begin{equation}
dQ = \frac{R}{\gamma -1}dT - RT \frac{d
\rho}{\rho} \rho}{\rho}.
\end{equation}
We can rewrite
\begin{equation}
\frac{d\rho}{rho} = \frac{1}{\rho} \frac{dP}{RT} - \frac{1}{\rho}\frac{P}{RT^2} dT
\end{equation}
Let's also introduce the enthalpy $h$ in the limit that the number of particles in the system is constant,
\begin{equation}
dh = TdS + VdP = TdS + \frac{dP}{\rho}
...
\begin{equation}
dG = SdT + \frac{dP}{\rho}
\end{equation}
Now we assume to special cases, adiabatic and isothermal flows. First assume an adiabatic flow, $dQ =0$. Then