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Matt Pitkin edited We_can_define_the_Fourier__.tex
over 8 years ago
Commit id: 42958cd02d0b7737498614ebd473075c05add127
deletions | additions
diff --git a/We_can_define_the_Fourier__.tex b/We_can_define_the_Fourier__.tex
index 83e2b2f..5ddbbad 100644
--- a/We_can_define_the_Fourier__.tex
+++ b/We_can_define_the_Fourier__.tex
...
\end{equation}
so, ${\rm d}t = A{\rm d}z$ and therefore in equation~\ref{eq:fourier2} we have $y_k' = Ay_k$. If we make the substitution into equation~\ref{eq:subst} then we get
\begin{equation}\label{eq:Mexpanded}
M = A^3az^3 + A^2(3Ba + b)z^2 + A(3B^2a + 2Bb + c)z +
B(B^2 B(B^2a + Bb + c) + d.
\end{equation}
If we equation the terms in equation~\ref{eq:Mexpanded} with those in exponential term within the integral in equation~\ref{eq:fourier2} we get
\begin{align}
...
and
\begin{align}
\alpha &= A(3B^2a + 2Bb + c), \nonumber \\
\beta &=
B(B^2 B(B^2a + Bb + c) + d. \label{eq:secondterms}
\end{align}
%This integral is not analytic, but integral of cubic trigonometric functions (through e.g.\ use of \href{http://docs.sympy.org/latest/index.html}{sympy}) can be written as