Matt Pitkin added Expanding_out_alpha_we_get__.tex  over 8 years ago

Commit id: 1d4b1a126cf7d7d902aaed445f9397ceec95081b

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Expanding out $\alpha$ we get  \begin{align}  \alpha =& a^{-1/3}\left(\frac{b^2}{3a} - \frac{2b^2}{3a} + c\right), \nonumber \\  =& a^{-1/3}\left(c - \frac{b^2}{3a}\right), \nonumber \\  =& \left(\frac{\pi}{3}\ddot{f_k}\right)^{-1/3} \pi \left(2(f_k-f) - \frac{\dot{f_k}^2}{\ddot{f_k}} \right) \label{eq:alpha}.  \end{align}