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\subsection{Determining P}  The porosity,P, is found by using the equation \[ n=\sqrt{2-P}\] \\  Recall that n was found in correction $c_4$ as $n=1.2385$ and with some algebra it is found that $P=2-n^2=0.466$.  \Subsection{Error \subsection{Error  in n and P} Error in n is found by the equation   \[dn= \sqrt{\frac{\rho_s}{\rho}}\sqrt{\left(\frac{1}{c_4}\right)^2 dc_1^2 + \left(\frac{-c_1}{c_4^2}\right)^2 dc_4^2}=0.00712647\] so $n=1.239 \pm .007$  Error in P is found by \[dP=2ndn=0.0176523\] so $P=0.46 \pm 0.02$