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\end{itemize}  \subsection{Example of calculating p-value for study abroad stats}  We have that $H_0:p=0.35$ and H_A:$p>0.35$ \[z-score=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}=\frac{0.42-0.35}{\sqrt{\frac{0.35*0.65}{100}}}=1.47\]  and p-value\[Prob(\hat{p} > 0.42 \vert p=0.35=prob(z>1.47)=1-0.9292=0.0708\]