deletions | additions       diff --git a/mas ch.6.tex b/mas ch.6.tex  index 562368f..2b4231e 100644  --- a/mas ch.6.tex  +++ b/mas ch.6.tex 
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step 7\\  Percentage of female college bound seniors who scored 675 or more on the SAT are about $4\% $\\  \subsection{6.24}  $z=\frac{675-530}{100}=1.55$. $z=\frac{675-530}{100}=1.45$.  From a z score table we see tat probability is 0.9394.This 0.9265.This  gives the percentage less than 675 so to find percent greater than just take the compliment, $1-0.9394=0.0606=6\%$ $1-0.9265=0.0735=7.4\%$ \\  \subsection{6.27}  $z_{279}=$. Probability=0.8413.$z_{261}=-1$. Probability=0.1587. So probability being betwen 261 days and 279 is $0.8413-0.1587=.6826=68\%$\\  \subsection{6.32}  a)$z=\frac{39-38}{2}=0.5$,with probability=0.6915.To get 39 inches or more take the compliment,1-0.6915=0.3085=$31\%$\\  b)$z=0.Probability of 0.500(makes sense its half way of the distribution).So probability of being taller than 38 inches is $0.5=50\%$\\